use the information provided to write the standard form equation.

The general equation of a circle is given by
[tex](x-a)^2+(y-b)^2=r^2[/tex]Where (a, b) is coordinate of the center of the circle
and r = radius
The question in the image gives the following data
[tex]\begin{gathered} \text{center =(-11,13)} \\ \text{radius = 1} \end{gathered}[/tex]On comparing with the general formula
a = -11, b =13, r =1
The next step will be to substitute the values of a, b, and r into the general equation
so that we will obtain
[tex]\begin{gathered} (x-(-11))^2+(y-13)^2=1^2\text{ } \\ (x+11)^2+(y-13)^2\text{ = 1} \end{gathered}[/tex]The correct option is Option D