Respuesta :

The general equation of a circle is given by

[tex](x-a)^2+(y-b)^2=r^2[/tex]

Where (a, b) is coordinate of the center of the circle

and r = radius

The question in the image gives the following data

[tex]\begin{gathered} \text{center =(-11,13)} \\ \text{radius = 1} \end{gathered}[/tex]

On comparing with the general formula

a = -11, b =13, r =1

The next step will be to substitute the values of a, b, and r into the general equation

so that we will obtain

[tex]\begin{gathered} (x-(-11))^2+(y-13)^2=1^2\text{ } \\ (x+11)^2+(y-13)^2\text{ = 1} \end{gathered}[/tex]

The correct option is Option D

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