Consider the schematic diagram given below,
Consider the following,
[tex]\begin{gathered} \angle BAD=\angle EDC\text{ (Corresponding angles)} \\ \angle ABE=\angle DCE\text{ (Right angles)} \\ \angle AEB=\angle DEC\text{ (Common)} \end{gathered}[/tex]So, by the AAA criteria, triangles ABE and DCE are similar.
So their corresponding sides must be in proportion,
[tex]\begin{gathered} \frac{AB}{CD}=\frac{BE}{CE} \\ \frac{h}{5}=\frac{8}{2} \end{gathered}[/tex]Thus, the required proportion is h/2 = 8/2.
Therefore, option B is the correct choice.