Question

assuming you have a 1.3M (molarity) solution of HNO3If you began with 0.6 liters of solution, and diluted the solution to a concentration of 0.45M, whatwould the final volume of the solution be?

Answer 1

Answer

The final volume of the solution be 2.13 liters

Explanation

Given:

Molarity of the stock HNO3 solution, C₁ = 1.3 M

Volume of the stock HNO3 solution, V₁ = 0.6 L

Molarity of the dilute HNO3 solution, C₂ = 0.45 M

What to find:

The final volume of the solution (i.e the volume of the dilute HNO3 solution, V₂)

Step-by-step solution:

The final volume of the solution can be calculated using the dilution formula.

$\begin{gathered} C_1V_1=C_2V_2 \\ \\ \Rightarrow V_2=\frac{C_1V_1}{C_2} \end{gathered}$

Plugging the values of the given parameters into the formula, we have;

$V_2=\frac{1.3M\times0.6L}{0.45M}=\frac{0.96L}{0.45}=2.13\text{ }L$

Therefore, the final volume of the solution be 2.13 liters