Answer
The final volume of the solution be 2.13 liters
Explanation
Given:
Molarity of the stock HNO3 solution, C₁ = 1.3 M
Volume of the stock HNO3 solution, V₁ = 0.6 L
Molarity of the dilute HNO3 solution, C₂ = 0.45 M
What to find:
The final volume of the solution (i.e the volume of the dilute HNO3 solution, V₂)
Step-by-step solution:
The final volume of the solution can be calculated using the dilution formula.
[tex]\begin{gathered} C_1V_1=C_2V_2 \\ \\ \Rightarrow V_2=\frac{C_1V_1}{C_2} \end{gathered}[/tex]Plugging the values of the given parameters into the formula, we have;
[tex]V_2=\frac{1.3M\times0.6L}{0.45M}=\frac{0.96L}{0.45}=2.13\text{ }L[/tex]Therefore, the final volume of the solution be 2.13 liters