Question

Solve the following absolute value equation. If needed, write your answer as a fraction reduced to lowest terms.

Answer 1

Equation

$\lvert-7y+4\rvert+8=1$

Isolate the absolute value

$\begin{gathered} \lvert-7y+4\rvert+8=1 \\ \lvert-7y+4\rvert=1-8 \\ \lvert-7y+4\rvert=-7 \end{gathered}$

Answer: No solution (∅) (absolute value cannot be less than 0).