You invested money in two funds. The first fund paid a dividend of 9% and the second 3%. You received 879. This year the fund paid 10% and 1% and you received 853. How much money did you invested in each fund?

You invested money in two funds The first fund paid a dividend of 9 and the second 3 You received 879 This year the fund paid 10 and 1 and you received 853 How class=

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The given information is:

- Last year you received a total of $879.

- The first fund paid a dividend of 9% and the second fund paid a dividend of 3%.

- This year you received a total of $853.

- The first fund paid a dividend of 10% and the second fund paid a dividend of 1%.

We can make an equation for the money you received each year.

Let's set x=money you invested in the first fund and y=money you invested in the second fund.

Then, last year dividend's equation is:

[tex]x*0.09+y*0.03=879\text{ Equation 1}[/tex]

Now, for this year the equation will be:

[tex]x*0.10+y*0.01=853\text{ Equation 2}[/tex]

Let's isolate y from equation 2:

[tex]\begin{gathered} 0.10x+0.01y=853 \\ 0.01y=853-0.10x \\ y=\frac{853-0.10x}{0.01} \end{gathered}[/tex]

Now, replace y into equation 1 and solve for x:

[tex]\begin{gathered} 0.09x+0.03(\frac{853-0.10x}{0.01})=879 \\ \\ 0.09x+3(853-0.10x)=879 \\ 0.09x+2559-0.30x=879 \\ -0.21x=879-2559 \\ -0.21x=-1680 \\ x=\frac{-1680}{-0.21} \\ \\ x=8000 \end{gathered}[/tex]

Replace x into y-equation and solve:

[tex]\begin{gathered} y=\frac{853-0.10*8000}{0.01} \\ \\ y=\frac{853-800}{0.01} \\ \\ y=\frac{53}{0.01} \\ \\ y=5300 \end{gathered}[/tex]

So, x=8000 and y=5300.

You invested $8000 in the first fund and $5300 in the second fund.

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