Question

A 58 V AC voltage source is connected across a 3.7 H inductor. What is the current through the inductor if the frequency is 63 Hz?

Answer 1

We will have the following:

First:

$x_l=2\pi(63Hz)(3.7H)\Rightarrow x_l=466.2\pi\Omega$

Then:

$\begin{gathered} I=\frac{58V}{466.2\pi\Omega}\Rightarrow I=0.03960097254...A \\ \\ \Rightarrow I\approx0.04A \end{gathered}$

So, the current is approximately 0.04 A.