Question

Write the equation in standard form for the circle passing through (2,3) centered at the origin

Answer 1

Given

coordinates (2, 3) and centre points (0,0)

Find

Equation of a circle

Explanation

As we know the standard equation for a circle with centre (h , k ) and r is a radius

$(x-h)^2+(y-k)^2=r^2$

since, center is (0 , 0) , the equation becomes

$x^2+y^2=r^2$

Now, we find the value of radius , it is can find by using the pythagoras theorem,

$r^2=2^2+3^2=4+9=13$

so,

$x^2+y^2=13$

Final Answer

The equation for a circle passing through (2, 3) is

$x^2+y^2=13$