Let:
[tex]\begin{gathered} y=0.05+20_{\text{ }}(1) \\ y=0.015x_{\text{ }}(2) \end{gathered}[/tex]Substitute (1) into (2):
[tex]\begin{gathered} 0.05+20=0.015x \\ solve_{\text{ }}for_{\text{ }}x\colon \\ 20.05=0.015x_{} \\ Divide_{\text{ }}both_{\text{ }}sides_{\text{ }}by_{\text{ }}0.015\colon \\ \frac{20.05}{0.015}=x \\ x=\frac{4010}{3}\approx1336.67 \end{gathered}[/tex]Replace the value of x into (2) in order to verify the answer:
[tex]y=0.015(\frac{4010}{3})=20.05[/tex]