Question

how do I solve negative 2 ninths minus negative 1

Answer 1

$-\frac{2}{9}-(-1)$

this can be rewritten like so

$-\frac{2}{9}+1$

start by remembering how to substract or add fractions.

$\frac{a}{b}\pm\frac{b}{c}=\frac{ac\pm bd}{bc}$

now apply the formula on your fraction

$\begin{gathered} -\frac{2}{9}+\frac{1}{1}=\frac{(-2\cdot1)+(9\cdot1)}{(9\cdot1)} \\ -\frac{2}{9}+\frac{1}{1}=\frac{-2+9}{9} \\ -\frac{2}{9}+\frac{1}{1}=\frac{7}{9} \end{gathered}$