Question

Shelley traveled 250 meters south in 45 seconds and then traveled 575 meters east in 55 seconds. What was themagnitude of Shelley's average velocity?(a) 1.7 m/s(b) 3.9 m/s(C) 6.3 m/s(d) 7.8 m/s

Answer 1

In order to calculate Shelley's average velocity, first let's find the distance between the start and finish point, using the Pythagorean theorem:

$\begin{gathered} x^2=250^2+575^2 \\ x^2=62500+330.625 \\ x^2=393125 \\ x=627 \end{gathered}$

Then, dividing this distance by the total amount of time spent, we have:

$\begin{gathered} \text{velocity}=\frac{x}{45+55} \\ \text{velocity}=\frac{627}{100} \\ \text{velocity}=6.3\text{ m/s} \end{gathered}$

Therefore the correct option is C.