Question

1) If a horizontal asymptote exists for this function, identify its location.4x3 + 6xF(x) =3x3 - 2x + 1A) y = 03B) y =B)-4C)y=Oy43D) Does Not Exist

Answer 1

ANSWER :

C. y = 4/3

EXPLANATION :

Note that in a rational function :

$f(x)=\frac{ax^n+...}{bx^m+...}$

If n = m, the horizontal asymptote is at y = a/b

From the problem, we have :

$f(x)=\frac{4x^3+6x}{3x^3-2x+1}$

Since the exponents are equal, 3 = 3

The horizontal asymptote will be at y = 4/3