Respuesta :

we have

2x^2+9x+10

Find the zeros of the quadratic function

Using the formula

we have

a=2

b=9

c=10

substitute

[tex]x=\frac{-9\pm\sqrt[\square]{9^2-4(2)(10)}}{2(2)}[/tex][tex]\begin{gathered} x=\frac{-9\pm\sqrt[\square]{1}}{4} \\ \\ x=\frac{-9\pm1}{4} \end{gathered}[/tex]

the values of x are

x=-2 and x=-5/2

therefore

[tex]2x^2+9x+10=2(x+2)(x+\frac{5}{2})=(x+2)(2x+5)[/tex]

the answer is

(x+2)(2x+5)

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