A group of six sixth-graders measure and record their heights.
The heights are 52, 62, 53, 61, 55, 53.
Mean : Mean is an average of the given numbers: a calculated central value of a set of numbers. It express as :
[tex]\text{Mean =}\frac{Sum\text{ of all entries}}{Total\text{ number of entries}}[/tex]The given data has six sixth graders, So total number of entries = 6
Substitute the value :
[tex]\begin{gathered} \text{Mean}=\frac{52+62+53+61+55+53}{6} \\ \text{Mean}=\frac{336}{6} \\ \text{Mean}=56 \end{gathered}[/tex]The mean of the recorded height is 56.
Median : It is the middle value of the given list of data, when arranged in an order.
The expression for the even number of observation is :
[tex]\text{Meadian}=\frac{(\frac{n}{2})^{th}term+\mleft\lbrace\frac{n}{2}+1\mright\rbrace^{th}term}{2}[/tex]Arrange the given height in the ascending order.
52, 53, 53, 55, 61, 62
Since number of terms = 6
Substitute n = 6
[tex]\begin{gathered} \text{Meadian}=\frac{(\frac{6}{2})^{th}term+\mleft\lbrace\frac{6}{2}+1\mright\rbrace^{th}term}{2} \\ \text{Median}=\frac{3^{th}term+4^{th}term}{2} \\ \text{Median}=\frac{53+55}{2} \\ \text{Median}=54 \end{gathered}[/tex]The median is 54
Answer :
Mean = 56
Median = 54