Question

Four wires running through the corners of a square with sides of length 9.581 cm carry equal currents, 4.403 A. Calculate the magnetic field at the center of the square.

Answer 1

Given:

The length of the side is l = 9.581 cm

The current is I = 4.403 A

To find the magnetic field at the center of the square.

Explanation:

The magnetic field at the center of the square can be calculated by the formula

$B\text{ = }\frac{2\sqrt{2}\mu_0I}{\pi l}$

Here, the constant is

$\mu_0=\text{ 4}\pi\times10^{-7}\text{ H/m}$

On substituting the values, the magnetic field will be

$\begin{gathered} B=\frac{2\sqrt{2}\times4\pi\times10^{-7}\text{ }\times4.403}{\pi\times9.581\times10^{-2}} \\ =\text{ 5.199 }\times10^{-5}\text{ T} \\ =51.99\text{ }\times10^{-6}\text{ T} \\ =51.99\text{ }\mu T \end{gathered}$