Respuesta :

Given:

[tex]\frac{y^{12}}{y^{12}}=???[/tex]

so, as the numerator = denominator

the value of the given equation = 1

[tex]\frac{y^{12}}{y^{12}}=y^{12-12}=y^0=1[/tex]

To find the value of y which satisfy the equation:

As the denominator must be not equal to zero

so, y is all real numbers except zero

So,

[tex]y=R-\mleft\{0\mright\}[/tex]

RELAXING NOICE
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