Given that:
- On the first day the school sold 5 senior citizen tickets and 3 student tickets for a total of $92.
- On the second day the school took in $72 by selling 3 senior citizen tickets and 3 student tickets.
Let be "x" the price (in dollars) of a senior citizen and "y" the price (in dollars) of a student ticket.
Using the data provided in the exercise, you can set up this System of Equations:
[tex]\begin{cases}5x+3y={92} \\ 3x+3y={72}\end{cases}[/tex]You can solve it using the Elimination Method:
1. Multiply the first equation by -1.
2. Add the equations.
Then:
[tex]\begin{gathered} \begin{cases}-5x-3y={-92} \\ 3x+3y={72}\end{cases} \\ --------- \\ -2x+0=-20 \\ -2x=-20 \end{gathered}[/tex]3. Solve for "x":
[tex]\begin{gathered} x=\frac{-20}{-2} \\ \\ x=10 \end{gathered}[/tex]4. Substitute the value of "x" into one of the original equations and solve for "y":
[tex]\begin{gathered} 3(10)+3y=72 \\ 3y=72-30 \\ \\ y=\frac{42}{3} \\ \\ y=14 \end{gathered}[/tex]Hence, the answer is:
- Price of a senior citizen ticket:
[tex]\text{ \$}10[/tex]- Price of a student ticket:
[tex]\text{ \$}14[/tex]