ANSWER
The mole of argon atoms that is present in 17.2L of argon is 0.7679 mole
STEP-BY-STEP EXPLANATION:
Given parameters
• The volume of argon at STP = 17.2L
,• Let x represents the mole of argon at STP
Recall that, 1 mole of a gas is equivalent to 22.4L at STP
The next thing is to establish a proportion between the number of moles and volume of the given gas
[tex]\begin{gathered} 1\text{mole }\rightarrow\text{ 22.4L} \\ x\text{ mole }\rightarrow\text{ 17.2L} \\ \text{Cross multiply} \\ 1\cdot\text{ }17.2\text{ = x }\cdot\text{ 22.4} \\ 17.2\text{ = 22.4x} \\ \text{Divide both sides by 22.4} \\ \frac{17.2}{22.4}\text{ =}\frac{22.4x}{22.4} \\ x\text{ = 0.7679 mole} \end{gathered}[/tex]Hence, the mole of argon atoms that is present in 17.2L of argon is 0.7679 mole
