Question

The length of a rectangle is 2m-5. Width is 4m-2. If the perimeter is 382 inches, find the length and the width.

Answer 1

Given:

• Length of a rectangle = 2m-5

,

• Width of the rectangle = 4m-2

,

• Perimeter of the rectangle = 382 Inches

We know that:

$\begin{gathered} Perimeter\; of\; a\; rectangle=2(\text{Length}+Wi\differentialD tth)th).th) \\ \text{Therefore:} \\ 382=2\left(2m-5+4m-2\right) \\ 382=2(2m+4m-5-2) \\ 382=2(6m-7) \\ 382=12m-14 \\ \text{Add 14 to both sides} \\ 382+14=12m-14+14 \\ 396=12m \\ \text{Divide both sides by 12} \\ m=33 \end{gathered}$