Let g represent gallons of water and let L represent loads.
Here, the gallons of water varies directly with the number of loads, thus we have:
g ∝ L
Now introduce a constant k:
g = kL
65 gallons is used to wash 5 loads, thus we have:
65 = k * 5
Let's solve for k:
65 = 5k
Divide both sides by 5:
[tex]\begin{gathered} \frac{65}{5}=\frac{5k}{5} \\ \\ 13=k \end{gathered}[/tex]To find the amount of water that will be used to wash 8 loads, we have:
g = kl
We are to find g, substitute 13 for k and 8 for l:
g = 13 x 8
g = 104
Therefore, to wash 8 loads, 104 gallons of water is needed.
ANSWER:
104