Question

I need help with my math

Answer 1

Given

Graph

Procedure

$\begin{gathered} 3x+2y=-6 \\ 2y=-6-3x \\ y=\frac{-3x-6}{2} \\ y=-\frac{3}{2}x-3 \\ \end{gathered}$

$\begin{gathered} 3y=2x+15 \\ y=\frac{2x+15}{3} \\ y=\frac{2}{3}x+\frac{15}{3} \\ y=\frac{2}{3}x+5 \\ \end{gathered}$

$\begin{gathered} y-4x=8 \\ y=4x+8 \end{gathered}$

$\begin{gathered} y-8=-\frac{1}{2}(x+4) \\ y-8=-\frac{1}{2}x-\frac{1}{2}4 \\ y=-\frac{1}{2}x-2+8 \\ y=-\frac{1}{2}x+6 \end{gathered}$

$\begin{gathered} 3x-4y=8 \\ 4y=-8+3x \\ y=\frac{3x-8}{4} \\ y=\frac{3}{4}x-\frac{8}{4} \\ y=\frac{3}{4}x-2 \end{gathered}$

$\begin{gathered} 6x-2y=10 \\ 2y=6x-10 \\ y=\frac{6x-10}{2} \\ y=\frac{6x}{2}-\frac{10}{2} \\ y=3x-5 \end{gathered}$