Given:
The coordinates of the points through which the line passes,
(x1, y1)=(-3, -3).
(x2, y2)=(4, -2).
The two point form of the equation of a line can be expressed as,
[tex]y-y1=\frac{y2-y1}{x2-x1}(x-x1)[/tex]Substitute the known values in the above equation.
[tex]\begin{gathered} y-(-3)=\frac{-2-(-3)}{4-(-3)}(x-(-3)) \\ y+3=\frac{-2+3}{4+3}(x+3) \\ y+3=\frac{1}{7}(x+3) \\ 7(y+3)=x+3 \\ 7y+7\times3=x+3 \\ 7y+21=x+3 \\ 7y=x+3-21 \\ 7y=x-18 \\ y=\frac{1}{7}x-\frac{18}{7} \end{gathered}[/tex]Therefore, the equation of the line is,
[tex]y=\frac{1}{7}x-\frac{18}{7}[/tex]
