Question

In the figure at the right, segment AB parallel to segment CD parallel segment EF. Find AE.

Answer 1

Given as shown in the figure:

AB || CD || EF

So,

$\begin{gathered} \frac{AC}{BD}=\frac{CE}{DF} \\ \\ \frac{10.3}{10}=\frac{CE}{10} \\ \\ CE=10.3 \\ \\ AE=AC+CE=10.3+10.3=20.6 \end{gathered}$