need help with letter B and letter C in the pictures

B)
We will have that the linear relationship between Celcius and Fahrenheit can be written as follows:
*First: We will interpret the values at freezing and boiling temperature as coordinates, that is: (0, 32) & (100, 212). Now, we find the slope determine by these values and then replace them in the following expression:
[tex]f-f_1=m(c-c_1)[/tex]That is:
[tex]m=\frac{212-32}{100-0}\Rightarrow m=\frac{9}{5}[/tex]Now, that we have the slope, we will use one of the points (0, 32) and replace:
[tex]f-32=\frac{9}{5}(c-0)\Rightarrow f=\frac{9}{5}c+32[/tex]So, this is the function that describes the linear relationship between Celsius and Fahrenheit. [In the functions f & c stand for Fahrenheit and celsius respectively].
**
C)
We will find the temperature in which Fahrenheit and Celsius equal as follows:
We will write the relationship from "both sides" (When solved for Celsius and when solved for Fahrenheit):
[tex]f=\frac{9}{5}c+32[/tex]&
[tex]c=(f-32)\cdot\frac{5}{9}[/tex]Now, we can use any of the equations [Both represent the same function] and solve as follows:
[tex]x=\frac{9}{5}x+32\Rightarrow-\frac{4}{5}x=32\Rightarrow x=-\frac{32\cdot5}{4}\Rightarrow x=-40[/tex][This is using the first equation]
[tex]x=\frac{5}{9}(x-32)\Rightarrow x=\frac{5}{9}x-\frac{160}{9}\Rightarrow\frac{4}{9}x=-\frac{160}{9}[/tex][tex]\Rightarrow x=-\frac{160\cdot9}{9\cdot4}\Rightarrow x=-40[/tex][This is using the second equation]
So, at the temperature that they are the same is -40.