Question

A customer at a sushi restaurant was examining the types of sushi rolls offered on the menu. Rolls vary by type of fish and level of spiciness. Rolls only contain one type of fish. Not spicy A little spicy Yellowtail 3 3 Salmon 4 5 What is the probability that a randomly selected sushi roll contains salmon and is labeled not spicy? Simplify any fractions

Answer 1

The probability that a randomly selected sushi roll contains salmon and is labeled not spicy is given by

$P(salmon\: and\: not\: spicy)=\frac{n(salmon\: and\: not\: spicy)}{n(\text{total)}}$

Where n(salmon and not spicy) is 4 (intersection of salmon and not spicy)

n(total) is the total number of sushi rolls

$n(total)=3+3+4+5=15$

So, the probability that a randomly selected sushi roll contains salmon and is labeled not spicy is

$P(salmon\: and\: not\: spicy)=\frac{n(salmon\: and\: not\: spicy)}{n(\text{total)}}=\frac{4}{15}$

Therefore, the probability that a randomly selected sushi roll contains salmon and is labeled not spicy is 4/15