Respuesta :

Answer:

289/900

Explanation:

The given expression is

[tex](-\frac{1}{3}+0.3(-\frac{1}{3})+1)^2[/tex]

First, we know that 0.3(-1/3) = (3/10)(-1/3) = -1/10, therefore the expression is equal to

[tex]\begin{gathered} (-\frac{1}{3}+\frac{3}{10}(-\frac{1}{3})+1)^2 \\ \\ (-\frac{1}{3}-\frac{1}{10}+1)^2 \end{gathered}[/tex]

Now, we need to add the fractions, so

[tex]\begin{gathered} (-\frac{1}{3}-\frac{1}{10}+\frac{10}{10})^2 \\ \\ (-\frac{1}{3}+\frac{-1+10}{10})^2 \\ \\ (-\frac{1}{3}+\frac{9}{10})^2 \\ \\ (\frac{-1(10)+3(9)}{3(10)})^2 \\ \\ (\frac{-10+27}{30})^2 \\ \\ (\frac{17}{30})^2 \end{gathered}[/tex]

Finally, find the square of the fraction

[tex]\begin{gathered} (\frac{17^2}{30^2}) \\ \\ \frac{289}{900} \end{gathered}[/tex]

Therefore, the answer is 289/900

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