The system of equations we have is:
[tex]\begin{gathered} -16y=4x \\ 4x+27y=11 \end{gathered}[/tex]Step 1. Substitute the first equation into the second equation.
We substitute the value of 4x by the value of -16y:
[tex]-16y+27y=11[/tex]Step 2. Solve the previous equation for y.
We add the like terms in the left side of the equation:
[tex]11y=11[/tex]Step 3. Divide both sides of the equation by 11:
[tex]\begin{gathered} \frac{11y}{11}=\frac{11}{11} \\ y=\frac{11}{11} \\ y=1 \end{gathered}[/tex]Step 4. Now that we know that y=1, we substitute this value into the first equation of the system of equations:
[tex]-16y=4x[/tex]since y=1, we get:
[tex]\begin{gathered} -16(1)=4x \\ -16=4x \end{gathered}[/tex]Step 5. Divide both sides of the equation by 4:
[tex]\begin{gathered} \frac{-16}{4}=\frac{4x}{4} \\ -4=x \end{gathered}[/tex]Step 6. Write the solution as an ordered pair.
We remember than an ordered pair has the general form:
[tex](x,y)[/tex]The first number is always the x value, and the second number is always the y value.
Since in this case, we have:
x=-4
and
y=1
The ordered pair will be:
[tex](-4,1)[/tex]Answer: (-4,1)