Answer:
(a)Slope: 4, y-intercept: (0, 8).
(b)Slope: 1/4, y-intercept: (0, 10).
(c)Neither
(d)D. The slopes are neither equal nor opposite reciprocals.
Explanation:
Given the equations for two lines.
[tex]\begin{gathered} 4x-y=-8 \\ y=\frac{1}{4}x+10 \end{gathered}[/tex]
We want to find the slopes and the y-intercept in coordinate form.
In order to do this, we compare the given lines with the slope-intercept form:
[tex]y=mx+b\text{ where m=slope, b=y-intercept}[/tex]
Part A
[tex]\begin{gathered} 4x-y=-8 \\ \implies y=4x+8 \\ m=4 \\ b=8 \end{gathered}[/tex]
• The slope of the line, m = 4
,
• The y-intercept, (x, y) = (0, 8).
Part B
[tex]\begin{gathered} y=\frac{1}{4}x+10 \\ m=\frac{1}{4} \\ b=10 \end{gathered}[/tex]
• The slope of the line, m = 1/4
,
• The y-intercept, (x, y) = (0, 10).
Part C
• Two lines are said to be ,parallel, if they have the ,same slope,.
,
• Two lines are said to be ,perpendicular, if the ,product of their slopes is -1,.
From parts (a) and (b) above:
• The slope of the first line = 4
,
• The slope of the second line = 1/4
[tex]\begin{gathered} 4\neq\frac{1}{4} \\ 4\times\frac{1}{4}=1\neq-1 \end{gathered}[/tex]
Therefore, the lines are neither.
The reason for this is that the slopes are neither equal nor opposite reciprocals. (Option D).