Explanation
Step 1
find the equation of the line that passes through the points (-3, 0) and (-3 ,5)
a) find the slope of the line
the slope of a line is given by:
[tex]\begin{gathered} \text{slope}=\frac{\text{ changeiny}}{\text{changein x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ \text{and} \\ P2(x_2,y_2) \\ \text{are 2 well known points from the line} \end{gathered}[/tex]then, Let
P1(-3,0)
P2(-3,5)
replace
[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ slope=\frac{5-0}{-3-(-3)}=\frac{5}{0}=\text{indefined}\Rightarrow vertical\text{ line} \end{gathered}[/tex]therefore, the line is a vertical line
Step 2
now, to find the point where the line intersects the x-axis, check the x coomponent of any coordinate of the line,
so
[tex](-3,0)\Rightarrow-3[/tex]we need to draw a dashed vertical line that passes through and then, shaded the left zone, so
Inequalities that use < or > symbols are plotted with a dashed line to show that the line is not included in the region
therefore, the dashed zone represents all the x values smaller than -3
[tex]x<-3[/tex]I hope this helps you