In the isosceles triangle, the 2 base angles are equal in measures
Then in the isosceles triangle with a base angle of 74 degrees, the other base angle is also 74 degrees
Now we will find the measure of its vertex angle
74 + 74 + V = 180 degrees
148 + V = 180
Subtract 148 from both sides to find v
148 - 148 + V = 180 - 148
V = 32 degrees
Since this vertex angle is a part of a right angle, then
The vertex angle of the other isosceles triangle is
R + 32 = 90
Subtract 32 from both sides to find R
R + 32 - 32 = 90 - 32
R = 58
Noe let us find x
x + x + 58 = 180
2x + 58 = 180
Subtract 58 from both sides
2x + 58 - 58 = 180 - 58
2x = 122
Divide both sides by 2 to find x
2x/2 = 122/2
x = 61
The value of x is 61
