Question

A 4.0 L closed container holds 2.0 mole of an ideal gas at a certain temperature and pressure. Which closed container will hold 6.0 moles of this ideal gas at the same temperature and pressure?

Answer 1

Answer:

The volume of the container is 12L.

Explanation:

The given information from the exercise is:

- Initial volume: 4.0L

- Initial number of moles: 2.0 moles

- Final number of moles: 6.0 moles

To calculate the volume of a container with 6.0 moles, we can use a mathematical rule of three:

$\begin{gathered} 2.0moles-4.0L \\ 6.0moles-x=\frac{6.0moles*4.0L}{2.0moles} \\ x=12L \end{gathered}$

So, the container will have a volume of 12L.