Question

A wire carrying 19.6 amps of current has a length of 29.5 centimeters within a magnetic field of strength 0.946 teslasa. What is the force on the wire if it makes an angle with the magnetic field of 90.0 degrees? b. What is the force on the wire if it makes an angle with the magnetic field of 29.6 degrees?

Answer 1

Given:

Length , L = 29.5 cm

Current, I = 19.6 A

B = 0.946

Let's find the following:

(a). Force on the wire if it makes an angle with the magnetic field of 90.0 degrees.

To find the force, apply the formula

$F=BILsin\theta$

Where:

B is the magnetic field strength = 0.946 T

I is the current = 19.6 A

L is the length of the wire in meters.

Here, the length is in cm, let's convert from cm to m.

We have:

1 cm = 0.01 m

29.5 cm = 29.5 x 0.01 = 0.295 m

Plug in the values and solve for the force, F.

$\begin{gathered} F=0.946*19.6*0.295sin90 \\ \\ F=5.47\text{ N} \end{gathered}$

Therefore, the force when the angle is 90 degrees is 5.47 N.

• (b). The force on the wire when the angle is 29.6 degrees.

$\begin{gathered} F=0.946*19.6*0.295sin29.6 \\ \\ F=2.7\text{ N} \end{gathered}$

The force when it makes an angle of 29.6 degrees is 2.70 N.

ANSWER:

(a). 5.47 N

(b). 2.70 N