Please help with this problem.Solve for x.8x² + 5 = 35Round to the nearest hundredth.Enter your answers in the boxes.The solutions are approximately and .

The given equation is:
[tex]8x^2+5=35[/tex]1. Subtract 5 from both sides:
[tex]\begin{gathered} 8x^2+5-5=35-5 \\ 8x^2=30 \end{gathered}[/tex]2. Divide both sides by 8:
[tex]\begin{gathered} \frac{8x^2}{8}=\frac{30}{8} \\ \text{Simplify} \\ x^2=3.75 \end{gathered}[/tex]3. Take the square root of both sides:
[tex]\begin{gathered} \sqrt[]{x^2}=\sqrt[]{3.75} \\ \text{Simplify} \\ x=\pm1.94 \\ \text{The solutions are approximately} \\ x=1.94\text{ and x=-1.94} \end{gathered}[/tex]