Question

Select a CO2 car and measure the mass of the car. Record the physical features of the car and any identifying markings.Place a CO2 canister in the car and launch it down the track. The track length will be approximately 20 meters (roughly 66 feet). You will need a stopwatch to get the time of the car that goes the furthest down the track. Record your results of the other CO2 cars. Find velocity.

Answer 1

Answer:

v1 = 4.8 m/s

v2 = 7.3 m/s

v3 = 5 m/s

v4 = 4.3 m/s

v5 = 7 m/s

Explanation:

To complete the table, we will assume the mass of the cars, the physical description, the distance travel, and the time. However, we will calculate the velocity as:

$\text{Velocity = }\frac{\text{ Distance}}{\text{ Time}}$

Therefore, we can complete the table as follows:

Where the velocity of each trial was calculated as:

$\begin{gathered} v_1=\frac{19}{4}=4.8\text{ m/s} \\ v_2=\frac{22}{3}=7.3\text{ m/s} \\ v_3=\frac{25}{5}=5\text{ m/s} \\ v_4=\frac{17}{4}=4.25\text{ m/s} \\ v_5=\frac{21}{3}=7\text{ m/s} \end{gathered}$