Question

Your school wants to take out an ad in the papercongratulating the basketball team on a successfulseason, as shown to the right. The area of thephoto will be half the area of the entire ad. What isthe value of x?8 in5 inPhoto

Answer 1

Then twice area of the photo is whole area

First find the area of the photo

Photo area

$\begin{gathered} A=b\times h \\ A=8\times5 \\ A=40 \end{gathered}$

area of the photo is 40 square inches and whole area is

$40\times2=80$

80square inches

now find the whole area and replace 80

Ad area

$\begin{gathered} A=b\times h \\ 80=(8+x)(5+x) \\ \end{gathered}$

solve parenthesis

$\begin{gathered} (8\times5)+(8\times x)+(x\times5)+(x\times x)=80 \\ 40+8x+5x+x^2=80 \\ x^2+13x+40=80 \end{gathered}$

and equal to 0 to factor

$\begin{gathered} x^2+13x+40-80=0 \\ x^2+13x-40=0 \end{gathered}$

now we need to solve this equation to find the value of x

Value of X

we use quadratic formula

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

where a is 1, b is 13 and c -40

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