Question

Given the right triangle below, if AB = 11 and BC = 19, find AC. (round to nearest whole number)

Answer 1

$b.)\:22$

1) We can solve this problem, by using the Pythagorean Relation. So, let's do it.

$\begin{gathered} a^2=b^2+c^2 \\ \\ a^2=19^2+11^2 \\ \\ a^2=361+121 \\ \\ a^2=482 \\ \\ a=\sqrt{482} \\ \\ a=21.95\approx22 \end{gathered}$

Note that the line segment AC is the hypotenuse (the largest side).

2) Thus, the answer is:

$22$