If the group has 9 people and we want to calculate how many subgroups of 3 people can be done, we have a combination of 9 choose 3.
A combination of n choose p can be calculated with the formula below:
[tex]C(n,p)=\frac{n!}{p!(n-p)!}[/tex]So, for n = 9 and p = 3, we have:
[tex]C(9,3)=\frac{9!}{3!(9-3)!}=\frac{9\cdot8\cdot7\cdot6!}{3\cdot2\cdot6!}=84[/tex]Therefore 84 different committees can be made.