Question

Two positive integers that differ by 9 are in the ratio of 8 to 11 What is the value of the smaller of the two numbers ?

Answer 1

Given:

The difference between two positive integers is 9. The ratio of the two numbers is 8 to 11. The objective is to find the value of smaller of the two numbers.

Consider the smaller number as x. Since the numbers differ by 9, the larger number will be x+9.

Now, the ratio can be represented as,

$\frac{x}{x+9}=\frac{8}{11}$

Let's solve for x, to find the smaller number.

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