Hello I know this looks like a big list but I was just showing the directions it gave at the very top as you see. I need help with 17 or 18.

As given by the question
(17)
There are given that the equation
[tex]\sin (3\theta)=1[/tex]Now,
From the general solution for the given equation
[tex]3\theta=\frac{\pi}{2}+2\pi n[/tex]Then,
Solve above solution
So, divide by 3 on both side of the equation
[tex]\begin{gathered} 3\theta=\frac{\pi}{2}+2\pi n \\ \frac{3\theta}{3}=\frac{\frac{\pi}{2}+2\pi n}{3} \\ \theta=\frac{\pi}{6}+\frac{2\pi n}{3} \end{gathered}[/tex]Hence, the value of the given equation is shown below:
[tex]\theta=\frac{\pi}{6}[/tex]