Hello I know this looks like a big list but I was just showing the directions it gave at the very top as you see. I need help with 17 or 18.

Hello I know this looks like a big list but I was just showing the directions it gave at the very top as you see I need help with 17 or 18 class=

Respuesta :

As given by the question

(17)

There are given that the equation

[tex]\sin (3\theta)=1[/tex]

Now,

From the general solution for the given equation

[tex]3\theta=\frac{\pi}{2}+2\pi n[/tex]

Then,

Solve above solution

So, divide by 3 on both side of the equation

[tex]\begin{gathered} 3\theta=\frac{\pi}{2}+2\pi n \\ \frac{3\theta}{3}=\frac{\frac{\pi}{2}+2\pi n}{3} \\ \theta=\frac{\pi}{6}+\frac{2\pi n}{3} \end{gathered}[/tex]

Hence, the value of the given equation is shown below:

[tex]\theta=\frac{\pi}{6}[/tex]

RELAXING NOICE
Relax