Question

A negative charge of -6.0x10-6 C exerts an attractive force of 65 N on a second charge that is 0.05 maway. What is the magnitude of the second charge?

Answer 1

Given that

Force, F= 65 N

One charge, q1= -6 x 10^-6 C

Distance, r= 0.05 m

Using Coulomb's law,

$F=K\frac{q1q2}{r^2}$

Here, K is Coulomb's constant whose value is 9x10^9 Nm^2/C^2

and q2 is the second charge.

Substituting the values, we get

$undefined$