Question

A 220 m wire is cut into three pieces. The second piece is 2 times as long as the first. The third piece is 4 times as long as the second. How long is each piece?

Answer 1

Answer:

The first piece = 20m

The second piece = 40m

The third pice = 8x = 160m

Explanation:

Given:

Total length of wire = 220m

2nd piece = 2 times the 1st piece

3rd piece = 4 times the 2nd

To find:

The length of each of the piece

The wire was cut into 3:

1st piece + 2nd piece + 3rd piece = 220m

let the first length = x

2nd length = 2 (1st length) = 2(x)

2nd length = 2x

3rd length = 4(2nd piece) = 4(2x)

3rd length = 8x

$\begin{gathered} x\text{ + 2x + 8x = 220} \\ simplify: \\ 11x\text{ = 220} \end{gathered}$$\begin{gathered} divide\text{ both sides by 11:} \\ \frac{11x}{11}=\frac{220}{11} \\ x\text{ = 20} \end{gathered}$

The first piece = 20m

The second piece = 2x = 2(20) = 40m

The third pice = 8x = 8(20) = 160m