Answer:
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5} \textsf{Time (s),}\;t \phantom{\dfrac11}& \phantom{.}0 \phantom{.}& 2 & 4 & 6\\\cline{1-5} \textsf{Distance (yd)},\;d \phantom{\dfrac11}& 0 & 12 & 24 & 36\\\cline{1-5} \end{array}[/tex]
Step-by-step explanation:
Given equation:
[tex]d=6t[/tex]
where:
- d is the distance in yards.
- t is the time in seconds.
To complete the table, substitute each value of t into the given formula and solve for d:
[tex]t=2 \implies d=6(2)=12[/tex]
[tex]t=4 \implies d=6(4)=24[/tex]
[tex]t=6 \implies d=6(6)=36[/tex]
Enter the found values of d into the table:
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5} \textsf{Time (s),}\;t \phantom{\dfrac11}& \phantom{.}0 \phantom{.}& 2 & 4 & 6\\\cline{1-5} \textsf{Distance (yd)},\;d \phantom{\dfrac11}& 0 & 12 & 24 & 36\\\cline{1-5} \end{array}[/tex]
