Respuesta :
Answer:
[tex]\textsf{A.} \quad x < -4[/tex]
B. To graph the solution to the inequality on number line, place an open circle at -4 and shade to the left of the circle.
C. x = -5, x = -6
Step-by-step explanation:
Given inequality:
[tex]-6(x-3) > 42[/tex]
Part A
To solve the inequality, divide both sides by -6 (remembering to reverse the inequality symbol as we are dividing by a negative number):
[tex]\implies \dfrac{-6(x-3)}{-6} > \dfrac{42}{-6}[/tex]
[tex]\implies x-3 < -7[/tex]
Add 3 to both sides:
[tex]\implies x-3+3 < -7+3[/tex]
[tex]\implies x < -4[/tex]
Part B
When graphing an inequality on a number line:
- < or > : open circle.
- ≤ or ≥ : closed circle.
- < or ≤ : shade to the left.
- > or ≥ : shade to the right.
To graph the solution to the inequality on number line, place an open circle at -4 and shade to the left of the circle.
(See the attachment for the solution graphed on a number line).
Part C
Two values that would make the inequality true, are any values of x that are less than -4. For example:
- x = -5
- x = -6
We know the two values are solutions to the inequality as they are both included in the shaded part of the solution represented on the number line (from part B).
![Ver imagen semsee45](https://us-static.z-dn.net/files/d3c/93b33ebc6b4ffc7d5648bdb4ebf4d5b3.png)