Question

Determined which postulate or theorem can be used to prove that AABC = ADCB.

Answer 1

Solution:

The statement is given below as

$\Delta ABC\cong\Delta DCB$

From the image in the question, we can see that

$\begin{gathered} \angle BAC\cong BDC \\ \angle ACB\cong CBD \\ They\text{ share a common side} \\ BC \end{gathered}$

Concept:

If two angles and a nonincluded side of one triangle are congruent to two angles and a nonincluded side of a second triangle, then the triangles are congruent.

Hence,

With the statements above, the final answer is

$\Rightarrow AAS$

OPTION B is the right answer