Respuesta :

To get the answer, we will attempt to simplify the first expression into its simplest format.

[tex]\sqrt[]{\frac{126xy^5}{32x^3}}[/tex]

We begin by dividing both the numerator and the denominator by 2:

[tex]\sqrt[]{\frac{63xy^5}{16x^3}}[/tex]

Since x appears in both the numerator and the denominator, we can simplify such that

[tex]\frac{x}{x^3}=\frac{1}{x^2}[/tex]

Hence, we have the expression to be

[tex]\sqrt[]{\frac{63y^5}{16x^2}}[/tex]

Let us compare the both expressions to each other now:

[tex]\sqrt[]{\frac{63y^5}{16x^2}}=\sqrt[]{\frac{63y^5}{ax^b}}[/tex]

Therefore,

[tex]\begin{gathered} a=16 \\ b=2 \end{gathered}[/tex]

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