We can rewrite the square root as :
[tex]\sqrt[]{a}=a^{\frac{1}{2}}[/tex]Then:
[tex]\log _{2^{\frac{1}{2}^{}}}16=8[/tex]Use the next property:
[tex]\log _ax=y\text{ is equal to }a^y=x[/tex]Where a=2^(1/2), x=16 and y=8
Then:
[tex]\log _{2^{\frac{1}{2}^{}}}16=8\text{ is equal to (}2^{\frac{1}{2}})^8=16[/tex]Simplify the expression:
[tex]\text{(}2^{\frac{1}{2}})^8=2^4^{}[/tex]Then:
[tex]2^4=16[/tex]