If 110j of energy are added to a 14.2 gram sample initially at 20.7 °c . the final temperature will be 36.89°C.
Given,
mass of chromium = m = 14.2g
initial temperature = T1 = 20.7°C
Q = m X C X ∆T
where,
Heat exchanged at Q
m = the sample's mass
C = sample specific heat, which for chromium is 0.460 J/goC.
Temperature change (T) = Tfinal - Tinitial.
So, We know,
106J = 13.8 X 0.460J/g°C X (Tfinal - 20.2°C )
(Tfinal - 20.2oC ) = 106J / 13.8 X 0.460J/g°C = 16.69
Tfinal = 16.69°C + 20.2°C = 36.89°C
Hence, The final temperature will be 36.89°C.
Specific heat capacity is the energy required to increase temperature of material of a certain mass by 1°C, in the unit of J/(kg·K).
mathematically,
Q = mc∆T
Where Q is the amount of heat a body absorbs, m is the body's mass, and t is the temperature rise
C = A substance's specific heat capacity is determined by the material it is made of.
J kg-1 K-1 is the SI unit of specific heat.
Learn more about specific heat capacity here :
brainly.com/question/11783514
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