Question

Hanson is fixing up his home and must spend less than $6,900 to hire carpenters and painters. Carpenters charge $41 per hour and painters charge $16 per hour.
Select the inequality in standard form that describes this situation. Use the given numbers and the following variables.

Answer 1

A) The inequality for the situation is 41x + 16y < 6900

B) The painter can work less than 97 hours without exceeding the budget of Hanson.

Given,

The total money spend by Hanson = < $6900

The charge for carpenters = $41 per hour

The charge for painters = $16 per hour

A) We have to find an inequality for this situation.

Lets take,

Carpenters working hours = x

Painters working hours = y

So, the inequality will be like:

41x + 16y < 6900

B) Now, we have to find the number of hours the painter can work without exceeding his budget if he hires carpenter.

Carpenters working hours = 50

Then, the charge will be = 50 × 41 = 2050

Then,

6900 - 2050 = 4850

The balance amount will be less than 4850.

So, the working hours of painter:

y < 4850 / 50

y < 97

That is, the painter can work less than 97 hours without exceeding the budget of Hanson.

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The question is incomplete. Completed question is given below:

Hanson is fixing up his home and must spend less than $6,900 to hire carpenters and painters. Carpenters charge$41 per hour and painters charge $16 per hour.

Part A: Write an inequality to represent the situation.

Part B: If he hires a carpenter for 50 hours, what is the maximum number of hours the painter can work without exceeding his budget?