Respuesta :
The e. C=C stretch tends to be the least intense due to the lowest change in dipole moment.
In IR spectroscopy, the change in the dipole moment is the factor that has the greatest effect on the intensity of the stretch. The dipole moment for a certain bond is generally dictated by the difference in electronegativity of the bonded atoms - the larger the difference, the greater the dipole moment will be.
In the case of O-H bonds (whether in an alcohol or a carboxylic acid), as well as the C=O bond, there is a large difference between the very electronegative oxygen and the relatively small electronegativity of H and C. On the other hand, while the difference in electronegativity between H and C is small, it is still larger than 0, which is the difference in the C=C bond (unless there are electron-donating or -withdrawing groups attached to the olefine carbons), which makes the C-H stretch the more intense one.
You can learn more about the dipole moment here:
brainly.com/question/14140953
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