Question

Rank the following atoms in order of decreasing size (i.e., largest to smallest): Rb, F, Mg, B, N.

a. Rb > Mg > B>N>F
b. N > F > B> Mg > Rb
c. Rb > Mg > F>N> B
d. Mg > Rb > B>N>F
e. Rb > Mg > N>B>F

Answer 1

The correct ranking is a. Rb > Mg > B > N > F. This answer can be reached through analysis of each atom's position in the periodic table of elements.

Of the five atoms, Rb is obviously the largest one because it is located in the fifth period of the periodic table, while the rest are in the third (Mg) and the second one (B, N, and F) which means that Rb has the largest atomic radius as it has most electron levels. This eliminates options b) and d).

Mg is next because it is in the third period. B, N, and F are all in the second period, meaning that they have comparably similar atomic radii. However, as we go from left to right in the period, the atomic radius is reduced because the effective charge of the core increases, so B has a larger radius than N, and N has a larger radius than F.

You can learn more about the periodic table of elements here:
brainly.com/question/11155928

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