1. In 10 seconds a car accelerates 4m/s2 to 6 m/s. How fast was the car going before it accelerated?

2. An object at rest starts accelerating. If it travels 10 meters to end up going 20 m/s, what was its acceleration?

3. A car stops in 150 m. If it has an acceleration of –8m/s2, how long did it take to stop?

4. An object is thrown up into the air going 100 m/s. How fast is it going 1.5 seconds later?

5. A rock falls off a cliff and falls for 1 secs. How high is the cliff?

6. A person throws tennis ball 2 m/s straight up. How long does it take for it to come back to their hand?

7. A ball goes 400 m in 4 seconds. If was moving 10 m/s to begin with, what is its final velocity?

The term acceleration is defined as the rate of change of the velocity with time. We shall now look at the solution to each of the problems.

1) Using;

v = u + at

v = final velocity

u = initial velocity

a = acceleration

t = time

a = v - u/t = 6 - 4/10

a = 0.2 m/s^2

2) v^2 = u^2 + 2as

s = distance

u = initial velocity

a = acceleration

v =final velocity

Given that it started from rest u = 0 m/s

v^2 = 2as

a = v^2/2s

a = (20)^2/ 2 * 10

a = 20 m/s^2

3) This problem can not be solved because the initial velocity is missing

4) v = u + gt

v = 100 + (9.8 * 1.5)

v = 114.7 m/s

5) h = ut + 1/2 gt^2

Since it was dropped from a height u = 0 m/s

h = 1/2 gt^2

h = 0.5 * 9.8 * (1)^2

h = 4.9 m

6) v = u + gt

At the maximum height v = 0 m/s

u = gt

t = u /g

t = 2/9.8

t = 0.2 s

To go up and come back 2(0.2) = 0.4 s

7) s = ut + 1/2 at^2

400 = (10 * 4) + 0.5 * (4)^2 * a

400 = 40 + 8a

400 - 40/8 = a

a = 45 m/s^2

Using;

v = u + at

v = 10 + 45 * 4

v = 190 m/s

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